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X(4X-7)=36^2
We move all terms to the left:
X(4X-7)-(36^2)=0
We add all the numbers together, and all the variables
X(4X-7)-1296=0
We multiply parentheses
4X^2-7X-1296=0
a = 4; b = -7; c = -1296;
Δ = b2-4ac
Δ = -72-4·4·(-1296)
Δ = 20785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{20785}}{2*4}=\frac{7-\sqrt{20785}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{20785}}{2*4}=\frac{7+\sqrt{20785}}{8} $
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